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Through the centroid of an equilateral triangle, A line parallel to the base is drawn. On this line an arbitrary point P is taken inside the triangle. Let h denote the `bot^("lar")` distance of P from the base, `h_1 h_2` are `bot^("lar")` distances from other two sides then

A

`h=(h_(1)+h_(2))/(2)`

B

`h=sqrt(h_(1)h_(2))`

C

`h=(2h_(1)h_(2))/(h_(1)+h_(2))`

D

`h=((h+h_(2))sqrt(3))/(4)`

Text Solution

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a
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