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In triangle ABC, angle B = pi//3. " and...

In triangle ABC, `angle B = pi//3. " and " angle C = pi//4 `. Let D divide BC inernally in the ratio `1 : 3 `. Then `(sin angle BAD)/(sin angle CAD)` equals

A

`(1)/(2)`

B

`(3)/(4)`

C

`(1)/(sqrt(6))`

D

`(sqrt(2))/(sqrt(3))`

Text Solution

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The correct Answer is:
C
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