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In a triangle ABC, a^(2)+c^(2)=2002b^(2)...

In a triangle `ABC, a^(2)+c^(2)=2002b^(2)`, then `(cotA+cotC)/(cotB)` is equal to

A

`(1)/(2001)`

B

`(2)/(2001)`

C

`(3)/(2001)`

D

`(4)/(2001)`

Text Solution

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The correct Answer is:
B
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