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In a DeltaABC,sum(b+c)tan""A/2tan((B-C)/...

In a `DeltaABC,sum(b+c)tan""A/2tan((B-C)/2)=`

A

a

B

b

C

c

D

0

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • In a DeltaABC,(a+b+c)(tan""A/2+tan""B/2)=

    A
    `2c cot""C/2`
    B
    `2a cot""A/2`
    C
    `2b cot""B/2`
    D
    `tan""C/2`

  • In DeltaABC , tan""((A+B)/(2))*tan""(C)/(2)=

    A
    `sin 2A `
    B
    1
    C
    `tan 2A`
    D
    0

  • In DeltaABC,sum(r+r_1)tan((B-C)/2)=

    A
    `(abc)/Delta^3`
    B
    0
    C
    `4Rr^2`
    D
    `1//r`

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