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In a triangle ABC, angelA=30^(@), BC=2+ ...

In a triangle ABC, `angelA=30^(@), BC=2+ sqrt(5)`, then the distance of the vertex A from the orthocentre of the triangle is

A

1

B

`(2+sqrt(5))sqrt(3)`

C

`(sqrt(3)+1)/(2sqrt(2))`

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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