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In DeltaABC,("cot"(A)/(2)+"cot"(B)/(2))(...

In `DeltaABC,("cot"(A)/(2)+"cot"(B)/(2))(a "sin"^(2)(B)/(2)+b "sin"^(2)(A)/(2))=`

A

`cotC`

B

`c cotC`

C

`"cot"(C)/(2)`

D

`c "cot"(C)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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