f(x) = {{:((k cos x)/(pi - 2x) "if" , ...

`f(x) = {{:((k cos x)/(pi - 2x) "if" , x ne (pi)/(2)),( 3, "if" x=(pi)/(2)):}` at ` x= pi/2` , f (x) is containuous , find the value of k .

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