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A pure inductor of 25mH is connnected to...

A pure inductor of 25mH is connnected to a source of 220V and 50 Hz. Find the inductive reactance, rms value of current and peak current in the circuit.

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Here : `L=25x10^(-3)H,V_("rms")=220V,v=50Hz,X_(L)=?I_("rms")=?I_(0)=?`
Inductive reactance is `" "X_(L)=omegaL=2pi vL`
`=2xx3.14xx50xx25xx10^(-3)`
`=7850xx10^(-3)`
`X_(L)=7.850Omega`
rms value of current in the circuit is given by
`I_("rms")=(V_("rms"))/(X_(L))`
`=(220)/(7.850)`
`=28.025" A"`
Peak current in the circuit is
`I_(0)=sqrt(2)I_("rms")=1.414xx28.025`
`=39.627" A"`.
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