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A prism of angle 60^(0) produces angle o...

A prism of angle `60^(0)` produces angle of minimum deviation of `40^(0)`. What is its refractive index ? Calcualte the angle of incidence.

Text Solution

Verified by Experts

Here : `A=60^(0),D=40^(0),n=?,i=?`
we have
`n=(Sin((A+D)/(2)))/(Sin((A)/(2)))`
`=(Sin((60+40)/(2)))/(Sin((60)/(2)))`
`=(Sin(50))/(Sin(30))=(0.7660)/(0.5000)`
n = 1.532
At minimum deviation position
`i=(A+D)/(2)=(60+40)/(2)=50^(0)`
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