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Integrate the following functions: sin 3...

Integrate the following functions: sin 3x cos4x

Text Solution

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`sin 3x cos 4x = cos 4x sin 3x
=1/2[sin(4x+3x)-sin(4x-3x)]
=1/2[sin7x-sinx]
therefore `int sin3x cos4x dx`
=1/2[-cos(7x)/7+cosx]+c
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