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The solution set of -12 lt 4 -(3x)/(-5) ...

The solution set of `-12 lt 4 -(3x)/(-5) le 2 , x in R ` is

A

`(10/3,80/3]`

B

`[-80/3,10/3)`

C

`(-80/3,-10/3]`

D

`(80/3,-10/3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the inequality \(-12 < 4 - \frac{3x}{-5} \leq 2\), we will break it down into steps. ### Step 1: Rewrite the inequality We start with the inequality: \[ -12 < 4 - \frac{3x}{-5} \leq 2 \] ### Step 2: Simplify the inequality We can rewrite the inequality as two separate inequalities: 1. \(-12 < 4 - \frac{3x}{-5}\) 2. \(4 - \frac{3x}{-5} \leq 2\) ### Step 3: Solve the first inequality For the first inequality: \[ -12 < 4 - \frac{3x}{-5} \] Subtract 4 from both sides: \[ -12 - 4 < -\frac{3x}{-5} \] This simplifies to: \[ -16 < -\frac{3x}{-5} \] Multiplying both sides by -5 (remember to flip the inequality sign): \[ 80 > 3x \] or \[ 3x < 80 \] Dividing by 3: \[ x < \frac{80}{3} \] ### Step 4: Solve the second inequality Now for the second inequality: \[ 4 - \frac{3x}{-5} \leq 2 \] Subtract 4 from both sides: \[ -\frac{3x}{-5} \leq 2 - 4 \] This simplifies to: \[ \frac{3x}{5} \leq -2 \] Multiplying both sides by 5: \[ 3x \leq -10 \] Dividing by 3: \[ x \leq -\frac{10}{3} \] ### Step 5: Combine the results Now we have two inequalities: 1. \(x < \frac{80}{3}\) 2. \(x \leq -\frac{10}{3}\) Since \(x\) must satisfy both conditions, we combine them: \[ -\frac{10}{3} \leq x < \frac{80}{3} \] ### Final Answer Thus, the solution set is: \[ x \in \left[-\frac{10}{3}, \frac{80}{3}\right) \]
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