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Two finite sets A and B are such that As...

Two finite sets A and B are such that `AsubB`, then which of the following is not correct?

A

`a. AuuB=B`

B

b. `AnnB=A`

C

c. `A-B=phi`

D

d. `B-A=phi`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the properties of two finite sets A and B, given that A is a subset of B (denoted as \( A \subseteq B \)). We will evaluate each of the provided options to determine which statement is not correct. ### Step-by-Step Solution: 1. **Understanding the relationship \( A \subseteq B \)**: - Since \( A \) is a subset of \( B \), every element in \( A \) is also in \( B \). This implies that \( B \) contains all elements of \( A \) and possibly more. 2. **Evaluating Option A: \( A \cup B = B \)**: - The union of sets \( A \) and \( B \) is defined as the set containing all elements that are in \( A \), in \( B \), or in both. - Since \( A \) is a subset of \( B \), the union \( A \cup B \) will simply be \( B \). - **Conclusion**: This statement is correct. 3. **Evaluating Option B: \( A \cap B = A \)**: - The intersection of sets \( A \) and \( B \) is defined as the set containing all elements that are in both \( A \) and \( B \). - Since all elements of \( A \) are in \( B \), the intersection \( A \cap B \) will be exactly \( A \). - **Conclusion**: This statement is correct. 4. **Evaluating Option C: \( A - B = \emptyset \)**: - The difference \( A - B \) represents the elements that are in \( A \) but not in \( B \). - Since \( A \) is a subset of \( B \), there are no elements in \( A \) that are outside of \( B \). - Therefore, \( A - B \) will indeed be the empty set \( \emptyset \). - **Conclusion**: This statement is correct. 5. **Evaluating Option D: \( B - A = \emptyset \)**: - The difference \( B - A \) represents the elements that are in \( B \) but not in \( A \). - Since \( B \) may contain elements that are not in \( A \) (as \( A \) is just a subset of \( B \)), there will be elements in \( B \) that are not in \( A \). - Thus, \( B - A \) cannot be the empty set \( \emptyset \). - **Conclusion**: This statement is not correct. ### Final Answer: The option that is not correct is **Option D: \( B - A = \emptyset \)**.
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