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Every body in a room shakes hands with e...

Every body in a room shakes hands with everybody else. The total number of handshakes is 21. The total number of persons in the room is

A

(a) 6

B

(b) 7

C

(c) 8

D

(d) 9

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The correct Answer is:
To solve the problem of finding the total number of persons in a room where every person shakes hands with every other person, and the total number of handshakes is 21, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: - Each handshake involves 2 people. If there are \( N \) people in the room, the number of unique handshakes can be calculated using combinations. 2. **Using the Combination Formula**: - The number of ways to choose 2 people from \( N \) is given by the combination formula: \[ \binom{N}{2} = \frac{N!}{(N-2)! \cdot 2!} \] - This simplifies to: \[ \binom{N}{2} = \frac{N(N-1)}{2} \] 3. **Setting Up the Equation**: - According to the problem, the total number of handshakes is 21. Therefore, we can set up the equation: \[ \frac{N(N-1)}{2} = 21 \] 4. **Eliminating the Fraction**: - To eliminate the fraction, multiply both sides by 2: \[ N(N-1) = 42 \] 5. **Rearranging the Equation**: - Rearranging gives us a quadratic equation: \[ N^2 - N - 42 = 0 \] 6. **Factoring the Quadratic**: - We need to factor the quadratic equation. We are looking for two numbers that multiply to -42 and add to -1. The numbers -7 and 6 work: \[ (N - 7)(N + 6) = 0 \] 7. **Finding the Solutions**: - Setting each factor to zero gives us: \[ N - 7 = 0 \quad \Rightarrow \quad N = 7 \] \[ N + 6 = 0 \quad \Rightarrow \quad N = -6 \] 8. **Interpreting the Results**: - Since \( N \) represents the number of persons, it cannot be negative. Therefore, we discard \( N = -6 \). 9. **Conclusion**: - The total number of persons in the room is: \[ N = 7 \] ### Final Answer: The total number of persons in the room is **7**. ---
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