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If the ratio of AM to GM of two positive...

If the ratio of AM to GM of two positive numbers a and b is 5:3, then a:b is

A

(a) `3:5`

B

(b) `2:9`

C

(c) `9:1`

D

(d) `5:3`

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The correct Answer is:
To solve the problem, we need to find the ratio \( a:b \) given that the ratio of the Arithmetic Mean (AM) to the Geometric Mean (GM) of two positive numbers \( a \) and \( b \) is \( 5:3 \). ### Step-by-Step Solution: 1. **Define the Arithmetic Mean (AM) and Geometric Mean (GM)**: - The Arithmetic Mean (AM) of \( a \) and \( b \) is given by: \[ AM = \frac{a + b}{2} \] - The Geometric Mean (GM) of \( a \) and \( b \) is given by: \[ GM = \sqrt{ab} \] 2. **Set up the ratio**: - According to the problem, the ratio of AM to GM is: \[ \frac{AM}{GM} = \frac{5}{3} \] - Substituting the expressions for AM and GM, we have: \[ \frac{\frac{a + b}{2}}{\sqrt{ab}} = \frac{5}{3} \] 3. **Cross-multiply to eliminate the fraction**: - Cross-multiplying gives: \[ 3(a + b) = 10\sqrt{ab} \] 4. **Rearranging the equation**: - We can rewrite this as: \[ 3a + 3b = 10\sqrt{ab} \] 5. **Square both sides to eliminate the square root**: - Squaring both sides results in: \[ (3a + 3b)^2 = (10\sqrt{ab})^2 \] - This simplifies to: \[ 9(a + b)^2 = 100ab \] 6. **Expand the left-hand side**: - Expanding \( (a + b)^2 \) gives: \[ 9(a^2 + 2ab + b^2) = 100ab \] - This leads to: \[ 9a^2 + 18ab + 9b^2 = 100ab \] 7. **Rearranging the equation**: - Rearranging gives: \[ 9a^2 + 9b^2 - 82ab = 0 \] 8. **Factoring the quadratic equation**: - This can be factored as: \[ 9a^2 - 81ab - 1ab + 9b^2 = 0 \] - Grouping terms: \[ 9a(a - 9b) - b(a - 9b) = 0 \] - Factoring out \( (a - 9b) \): \[ (a - 9b)(9a - b) = 0 \] 9. **Finding the solutions**: - Setting each factor to zero gives: - \( a - 9b = 0 \) which implies \( a = 9b \) - \( 9a - b = 0 \) which implies \( b = 9a \) 10. **Finding the ratio \( a:b \)**: - From \( a = 9b \), the ratio \( a:b \) is: \[ \frac{a}{b} = \frac{9b}{b} = 9:1 \] - From \( b = 9a \), the ratio \( a:b \) is: \[ \frac{a}{b} = \frac{a}{9a} = 1:9 \] 11. **Conclusion**: - The valid ratio from the options provided is \( 9:1 \). Thus, the final answer is: \[ \text{The ratio } a:b \text{ is } 9:1. \]
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ICSE-SEQUENCES AND SERIES-MULTIPLE CHOICE QUESTIONS
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  7. If 9 times the 9th term of an A.P. is equal to 13 times the 13 term, t...

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  8. If T(r) be the rth term of an A.P. with first term a and common differ...

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  9. The sum of all odd numbers between 1 and 1000 which are divisible by 3...

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  15. The first and second terms of a G.P are x^(-4) and x^(m) respectively....

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  16. If the first term of a G.P is 27 and 8th term is 1/81, then the sum of...

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  17. The product of 5 terms of G.P. whose 3rd term is 2 is

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