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The 10th common terms between the series...

The 10th common terms between the series `3+7+11+`….. And `1+6+11+`….. is
(i) 191
(ii) 193
(iii) 211
(iv) None of these

A

191

B

193

C

211

D

None of these

Text Solution

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The correct Answer is:
To find the 10th common term between the two series, we first need to identify the general terms of each series. ### Step 1: Identify the first series The first series is: 3, 7, 11, 15, 19, ... This is an arithmetic progression (AP) where: - First term (a₁) = 3 - Common difference (d₁) = 7 - 3 = 4 The nth term of an arithmetic series can be given by the formula: \[ a_n = a_1 + (n - 1) \cdot d \] For the first series: \[ a_n = 3 + (n - 1) \cdot 4 \] So, the nth term is: \[ a_n = 4n - 1 \] ### Step 2: Identify the second series The second series is: 1, 6, 11, 16, 21, ... This is also an arithmetic progression where: - First term (b₁) = 1 - Common difference (d₂) = 6 - 1 = 5 Using the same formula for the nth term: \[ b_n = 1 + (n - 1) \cdot 5 \] So, the nth term is: \[ b_n = 5n - 4 \] ### Step 3: Find common terms To find the common terms, we need to set the two nth terms equal to each other: \[ 4m - 1 = 5n - 4 \] Rearranging gives: \[ 4m - 5n = -3 \] ### Step 4: Solve for integer solutions We can rearrange this equation: \[ 4m = 5n - 3 \] \[ m = \frac{5n - 3}{4} \] For m to be an integer, \( 5n - 3 \) must be divisible by 4. We can check values of n to find integer values of m. ### Step 5: Find values of n Let’s check for n = 1, 2, 3, ... until we find the 10th common term: 1. n = 1: \( 5(1) - 3 = 2 \) (not divisible by 4) 2. n = 2: \( 5(2) - 3 = 7 \) (not divisible by 4) 3. n = 3: \( 5(3) - 3 = 12 \) (divisible by 4, m = 3) 4. n = 4: \( 5(4) - 3 = 17 \) (not divisible by 4) 5. n = 5: \( 5(5) - 3 = 22 \) (not divisible by 4) 6. n = 6: \( 5(6) - 3 = 27 \) (not divisible by 4) 7. n = 7: \( 5(7) - 3 = 32 \) (divisible by 4, m = 8) 8. n = 8: \( 5(8) - 3 = 37 \) (not divisible by 4) 9. n = 9: \( 5(9) - 3 = 42 \) (not divisible by 4) 10. n = 10: \( 5(10) - 3 = 47 \) (not divisible by 4) 11. n = 11: \( 5(11) - 3 = 52 \) (divisible by 4, m = 13) 12. n = 12: \( 5(12) - 3 = 57 \) (not divisible by 4) 13. n = 13: \( 5(13) - 3 = 62 \) (not divisible by 4) 14. n = 14: \( 5(14) - 3 = 67 \) (not divisible by 4) 15. n = 15: \( 5(15) - 3 = 72 \) (divisible by 4, m = 18) Continuing this process, we find the common terms: - 1st common term: 11 - 2nd common term: 31 - 3rd common term: 51 - 4th common term: 71 - 5th common term: 91 - 6th common term: 111 - 7th common term: 131 - 8th common term: 151 - 9th common term: 171 - 10th common term: 191 ### Step 6: Conclusion The 10th common term is: \[ \text{10th common term} = 191 \] ### Final Answer Thus, the answer is option (i) 191. ---
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ICSE-SEQUENCES AND SERIES-MULTIPLE CHOICE QUESTIONS
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  2. In an AP the pth term is q and the (p+q)th term is zero, then the qth ...

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  3. The 10th common terms between the series 3+7+11+….. And 1+6+11+….. is ...

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  4. If the sum of n terms of an A,Pis given by S(n) =3n+2n^(2) then the co...

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  5. If 9 times the 9th term of an A.P. is equal to 13 times the 13 term, t...

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  6. If T(r) be the rth term of an A.P. with first term a and common differ...

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  7. The sum of all odd numbers between 1 and 1000 which are divisible by 3...

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  8. The sum of all two digit numbers which when divided by 4 leave 1 as re...

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  9. If log(3)2,log(3)(2^(x)-5) and log(3)(2^(x)-7/2) are in A.P., then x i...

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  10. Let a,b,c be in A.P. If p is the A.M. between a and b and q is the A.M...

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  11. If the ratio of second to seventh of n A.M.'s between -7 and 65 is 1:7...

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  12. In a G.P first term is 3/4, common ratio is 2 and the last term is 384...

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  13. The first and second terms of a G.P are x^(-4) and x^(m) respectively....

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  14. If the first term of a G.P is 27 and 8th term is 1/81, then the sum of...

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  15. The product of 5 terms of G.P. whose 3rd term is 2 is

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  16. If 3rd, 8th and 13th terms of a G.P are p ,q and r respectively, then ...

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  17. Let a,b,c are in A.P and k!=0 be a real number which of the following ...

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  18. How many two digit numbers are divisible by 4?

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  19. A G.P consists of 200 terms. If the sum of odd terms of G.P is m and s...

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  20. If an infinite G.P. has the first term a and the sum 5, then which one...

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