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Let a,b,c be in A.P. If p is the A.M. be...

Let a,b,c be in A.P. If p is the A.M. between a and b and q is the A.M between b and c, then b is equal to

A

A. `(p+q)/2`

B

B. `(p-q)/2`

C

C. `(pq)/2`

D

D. None of these

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To solve the problem, we need to find the value of \( b \) given that \( a, b, c \) are in Arithmetic Progression (A.P.), and \( p \) and \( q \) are the Arithmetic Means (A.M.) between \( a \) and \( b \), and between \( b \) and \( c \) respectively. ### Step-by-Step Solution: 1. **Understanding A.P.**: Since \( a, b, c \) are in A.P., we know that: \[ 2b = a + c \quad \text{(Equation 1)} \] 2. **Finding A.M. between \( a \) and \( b \)**: The A.M. \( p \) between \( a \) and \( b \) can be expressed as: \[ p = \frac{a + b}{2} \] Multiplying both sides by 2 gives: \[ a + b = 2p \quad \text{(Equation 2)} \] 3. **Finding A.M. between \( b \) and \( c \)**: The A.M. \( q \) between \( b \) and \( c \) can be expressed as: \[ q = \frac{b + c}{2} \] Multiplying both sides by 2 gives: \[ b + c = 2q \quad \text{(Equation 3)} \] 4. **Adding Equations**: Now, we will add Equation 2 and Equation 3: \[ (a + b) + (b + c) = 2p + 2q \] This simplifies to: \[ a + 2b + c = 2p + 2q \] 5. **Substituting Equation 1**: From Equation 1, we know \( a + c = 2b \). We can substitute this into the equation: \[ 2b + 2b = 2p + 2q \] This simplifies to: \[ 4b = 2p + 2q \] 6. **Solving for \( b \)**: Dividing both sides by 4 gives: \[ b = \frac{p + q}{2} \] ### Final Answer: Thus, the value of \( b \) is: \[ b = \frac{p + q}{2} \]
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