The vapour pressure of `H_(2)O` is `23.756`mmHg at `25^(@)C`. What is the vapour pressure of a solution of `28.5g` of sucrose, `C_(12)H_(22)O_(11)(342)` in `100g` of `H_(2)O` ?

Explanation

To find the vapor pressure of a solution of sucrose in water, we can follow these steps:

### Step 1: Calculate the number of moles of sucrose (C₁₂H₂₂O₁₁)
We are given the mass of sucrose as 28.5 g and its molar mass as 342 g/mol.

\[ \text{Number of moles of sucrose} = \frac{\text{mass}}{\text{molar mass}} = \frac{28.5 \, \text{g}}{342 \, \text{g/mol}} = 0.0833 \, \text{moles} \]
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