The vapour pressure of a dilute solution of glucose `(C_(6)H_(12)O_(6))` is 750 mm Hg at `373K` . Calculate (i) molality and (ii) mole fraction of the solute.

Explanation

To solve the problem, we need to calculate both the molality and the mole fraction of the solute (glucose) in the dilute solution.

### Step-by-Step Solution:

**Step 1: Determine the decrease in vapor pressure.**
- The normal vapor pressure of pure water (P₀) at 373 K is given as 760 mm Hg.
- The vapor pressure of the solution (Pₛ) is given as 750 mm Hg.
- The decrease in vapor pressure (ΔP) can be calculated as:
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