Calculate the osmotic pressure of a decinormal solution of cane sugar at `0^(@)C`.

Explanation

To calculate the osmotic pressure of a decinormal solution of cane sugar at 0°C, we can follow these steps:

### Step 1: Understand the given data
- **Normality (N)** of the solution is given as 0.1 N (decinormal).
- Cane sugar (sucrose) is a non-electrolyte, meaning it does not dissociate in solution. Therefore, the molarity (M) is the same as the normality for this case.
- The temperature is given as 0°C, which needs to be converted to Kelvin.

### Step 2: Convert temperature to Kelvin
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