2g of benzoic acid dissolved in 25g of benzene produces a freezing-point depression of `1.62^(@)`. Calculate the molecular weight. Compare this with the molecular weight obtained from the formula for benzoic acid, `C_(6)H_(5)COOH`. `(K_(f)=4.90)`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Freezing Point Depression Formula
The freezing point depression (\( \Delta T_f \)) is given by the formula:
\[ \Delta T_f = K_f \cdot m \]
where:
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