What is the weight of 1 mole of a solute, `0.132g` of which in `29.7g` of benzene, gave a freezing-point depression of `0.108^(@)C` ?
(`K_(f)` for benzene `=5.12`)

Explanation

To find the weight of 1 mole of the solute, we can use the depression of freezing point formula and the information provided in the question. Here’s a step-by-step solution:

### Step 1: Write down the formula for freezing point depression
The formula for freezing point depression is given by:
\[ \Delta T_f = K_f \cdot m \]
where:
...