A mixture which contains `0.550g` of camphor and `0.045g` of an organic solute freezes at `157^(@)C` . The solute contains `93.46%` of C and `6.54%` of `H` by weight . What is the molecular formula of the compound ? (Freezing point of camphor `=178.4^(@)C` and `K_(f)=37.70`)

Explanation

To determine the molecular formula of the organic solute, we will follow these steps:

### Step 1: Calculate the depression in freezing point (ΔTf)
The depression in freezing point can be calculated using the formula:
\[ \Delta T_f = T_f^{\text{pure}} - T_f^{\text{solution}} \]
Where:
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