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When 400g of a 20% solution was cooled ,...

When 400g of a `20%` solution was cooled , 50g of the solute precipitated. What is the per cent concentration of the remaining solution ?

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To solve the problem, we will follow these steps: ### Step 1: Calculate the amount of solute in the original solution The original solution is 400 g with a concentration of 20%. \[ \text{Amount of solute} = \text{Total mass of solution} \times \left(\frac{\text{Percentage concentration}}{100}\right) \] \[ \text{Amount of solute} = 400 \, \text{g} \times \left(\frac{20}{100}\right) = 80 \, \text{g} \] ### Step 2: Determine the amount of solute remaining after precipitation From the problem, we know that 50 g of the solute precipitated. \[ \text{Remaining solute} = \text{Initial solute} - \text{Precipitated solute} \] \[ \text{Remaining solute} = 80 \, \text{g} - 50 \, \text{g} = 30 \, \text{g} \] ### Step 3: Calculate the mass of the remaining solution The total mass of the solution remains the same (400 g), but we need to account for the mass of the solute that has precipitated. \[ \text{Mass of remaining solution} = \text{Total mass of solution} - \text{Precipitated solute} \] \[ \text{Mass of remaining solution} = 400 \, \text{g} - 50 \, \text{g} = 350 \, \text{g} \] ### Step 4: Calculate the percentage concentration of the remaining solution Now we can calculate the percentage concentration of the remaining solution using the formula: \[ \text{Percentage concentration} = \left(\frac{\text{Remaining solute}}{\text{Mass of remaining solution}}\right) \times 100 \] \[ \text{Percentage concentration} = \left(\frac{30 \, \text{g}}{350 \, \text{g}}\right) \times 100 \approx 8.57\% \] ### Final Answer The percentage concentration of the remaining solution is approximately **8.57%**. ---
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