The mole fraction of a solute in a solutions is `0.1`. At `298K` molarity of this solution is the same as its molality. Density of this solution at 298 K is `2.0 g cm^(-3)`. The ratio of the molecular weights of the solute and solvent, `(MW_("solute"))/(MW_("solvent"))` is

Answer

9

Explanation

`(n_(1))/(n_(1)+n_(2))=0.1` and `(n_(1)xx1000)/((n_(1)M_(1)+n_(2)M_(2))d)=(n_(1)xx1000)/(n_(2)M_(2))`.