An element exists in the body-centred cubic structure whose cell edge is 2.88 A. The density of the element is 7.20 `g`/`cm^2`. Calculate the number of atoms in 104 g of the element.

Explanation

To solve the problem step-by-step, we will use the formula for density and the properties of the body-centered cubic (BCC) structure.

### Step 1: Understand the BCC Structure
In a body-centered cubic (BCC) structure, there are 2 atoms per unit cell. This is denoted as \( z = 2 \).

### Step 2: Write the Density Formula
The formula for density (\( \rho \)) in terms of the number of atoms, molar mass (M), and volume of the unit cell (A³) is given by:
\[
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