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What is the number of moles of Fe (OH)(...

What is the number of moles of Fe `(OH)_(3)` (s) that can be produced by allowing 1 mole of `Fe_(2)S_(3)` , 2 moles of `H_(2) O ` and 3 moles of `O_(2)` to react?
`2 Fe_(2) S_(3) (s) + 6H_(2) O (1) + 3O_(2) (g) to 4Fe (OH)_(3) (s) + 65 (s)`

Text Solution

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From the given mole ratio of `Fe_(2)S_(3) , H_(2) O and O_(2)` (i.e., 1 : 2 : 3) and mole ratio in the reaction , (i.e.,e: 6 : 3) it is clear that `H_(2) O` is the limiting reagent as `H_(2)O` shall be fully consumed in the reaction. Thus,
moles of `Fe(OH)_(3)` produced by 2 moles of `H_(2) O = (4)/(6) xx 2 = 1. 34`
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