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C(2) H(5) OH + Cr(2) O(7)^(2-) + H^(+)= ...

`C_(2) H_(5) OH + Cr_(2) O_(7)^(2-) + H^(+)= Cr^(3+) + C_(2) H_(4) O + H_(2)O`

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`3C_(2) H_(5) OH + Cr_(2) O_(7)^(2-) + 8 H^(+)= 2 Cr^(3+) + 3 C_(2) H_(4) O + 7 H_(2) O `
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Cr_(2) O_(7)^(2-) + C_(2) O_(4)^(2-) + H^(+) = Cr^(3+) + CO_(2) + H_(2) O

Cr_(2) O_(7)^(2-) + SO_(2) + H^(+) = Cr^(3+) + HSO_(4)^(-) + H_(2) O

Knowledge Check

  • In this reaction SO_(2) is (i) SO_(2)+2H_(2)S to 3S+3H_(2)O (ii) 3SO_(2)+Cr_(2)O_(7)^(2-)+2H^(+) to 2Cr^(3+)+3SO_(4)^(2-)+H_(2)O

    A
    oxidizing agent both in (i) and (ii)
    B
    oxidizing agent in (i) and reducing agent in (ii)
    C
    reducing agent both in (i) and (ii)
    D
    reducing agent in (i) and oxidizing agent in (ii)

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