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If y=cos^(-1)((sqrt(x)-1)/(sqrt(x)+1))+c...

If `y=cos^(-1)((sqrt(x)-1)/(sqrt(x)+1))+cosec^(-1)((sqrt(x)+1)/(sqrt(x)-1))` , then `(dy)/(dx)` is equal to

A

`(pi)/(2)`

B

0

C

1

D

none of these

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The correct Answer is:
To find the derivative \( \frac{dy}{dx} \) for the given function \[ y = \cos^{-1}\left(\frac{\sqrt{x}-1}{\sqrt{x}+1}\right) + \csc^{-1}\left(\frac{\sqrt{x}+1}{\sqrt{x}-1}\right), \] we can simplify the expression using properties of inverse trigonometric functions. ### Step 1: Recognize the relationship between inverse trigonometric functions We know that: \[ \cos^{-1}(a) + \sin^{-1}(a) = \frac{\pi}{2} \] for any \( a \) in the domain of these functions. ### Step 2: Rewrite the expression Notice that: \[ \csc^{-1}(x) = \sin^{-1}\left(\frac{1}{x}\right) \] Thus, we can rewrite \( \csc^{-1}\left(\frac{\sqrt{x}+1}{\sqrt{x}-1}\right) \) as: \[ \sin^{-1}\left(\frac{1}{\frac{\sqrt{x}+1}{\sqrt{x}-1}}\right) = \sin^{-1}\left(\frac{\sqrt{x}-1}{\sqrt{x}+1}\right) \] ### Step 3: Combine the expressions Now we can combine the two parts of \( y \): \[ y = \cos^{-1}\left(\frac{\sqrt{x}-1}{\sqrt{x}+1}\right) + \sin^{-1}\left(\frac{\sqrt{x}-1}{\sqrt{x}+1}\right) \] Using the identity from Step 1, we have: \[ y = \frac{\pi}{2} \] ### Step 4: Differentiate Since \( y \) is a constant (\( \frac{\pi}{2} \)), we find the derivative: \[ \frac{dy}{dx} = 0 \] ### Final Answer Thus, the derivative \( \frac{dy}{dx} \) is equal to: \[ \boxed{0} \]
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ICSE-CONTINUITY AND DIFFERENTIABILITY -MULTIPLE CHOICE QUESTIONS
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