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450 toys are divided into three types A,...

450 toys are divided into three types A, B & C. All three types of toys are sold at the profit of` 9%, 10% and 12% `respectively. Overall profit from type A and B is `9 3/7` % . Overall profit from all three types is 10%. Find the number of toys kept in all three categories A, B & C.

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To solve the problem step by step, we will use the concept of alligation to find the number of toys in each category A, B, and C. ### Step 1: Understand the Given Information - Total number of toys = 450 - Profit percentages: - Type A = 9% - Type B = 10% - Type C = 12% - Overall profit from types A and B = \(9 \frac{3}{7}\)% = \(9.42857\)% (converting mixed fraction to decimal) - Overall profit from all three types = 10% ### Step 2: Calculate the Profit from Types A and B Let the number of toys in type A be \(x\) and in type B be \(y\). The profit from type A and B can be calculated as follows: \[ \text{Total Profit from A and B} = \frac{x \times 9 + y \times 10}{x + y} \] According to the problem, this total profit is equal to \(9 \frac{3}{7}\)%: \[ \frac{x \times 9 + y \times 10}{x + y} = 9.42857 \] ### Step 3: Set Up the Equation Cross-multiplying gives: \[ x \times 9 + y \times 10 = 9.42857(x + y) \] This simplifies to: \[ 9x + 10y = 9.42857x + 9.42857y \] Rearranging gives: \[ (9 - 9.42857)x + (10 - 9.42857)y = 0 \] This simplifies to: \[ -0.42857x + 0.57143y = 0 \] ### Step 4: Solve for the Ratio of A and B Dividing through by 0.42857 gives: \[ y = \frac{0.42857}{0.57143}x \] Calculating this ratio gives: \[ y = \frac{3}{4}x \] Thus, the ratio of toys in A and B is \(x:y = 4:3\). ### Step 5: Express Total Toys in Terms of A and B Let \(x = 4k\) and \(y = 3k\). The total number of toys in A and B is: \[ x + y = 4k + 3k = 7k \] Since the total number of toys is 450, we have: \[ 7k + z = 450 \] Where \(z\) is the number of toys in type C. ### Step 6: Calculate the Number of Toys in Type C Now we need to find \(z\): \[ z = 450 - 7k \] ### Step 7: Calculate Overall Profit Including Type C The overall profit from all three types is given as 10%. Therefore, we can set up the equation: \[ \frac{4k \times 9 + 3k \times 10 + z \times 12}{450} = 10 \] Substituting \(z = 450 - 7k\): \[ \frac{4k \times 9 + 3k \times 10 + (450 - 7k) \times 12}{450} = 10 \] ### Step 8: Solve for k This simplifies to: \[ 4k \times 9 + 3k \times 10 + 450 \times 12 - 7k \times 12 = 4500 \] Calculating gives: \[ 36k + 30k + 5400 - 84k = 4500 \] Combining like terms: \[ -18k + 5400 = 4500 \] Solving for \(k\): \[ -18k = 4500 - 5400 \] \[ -18k = -900 \] \[ k = 50 \] ### Step 9: Calculate the Number of Toys in Each Category Now substituting \(k\) back to find \(x\), \(y\), and \(z\): - \(x = 4k = 4 \times 50 = 200\) - \(y = 3k = 3 \times 50 = 150\) - \(z = 450 - 7k = 450 - 350 = 100\) ### Final Answer - Number of toys in Type A = 200 - Number of toys in Type B = 150 - Number of toys in Type C = 100
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