` (2^(35))/(10) ` Find R .

( 35^(23^(23)))/(16) Find R .

(35^(40))/(100) Find R.

(10^(1)+10^(2)+10^(3)------+10^(100))/(6) find R.

Find the value and express as a rational number in standard form: (2)/(5)+(26)/(15) (ii) (10)/(3)+(-35)/(12)( iii -6+((-8)/(17))

Find 12xx35

If r^(th) term in the expansion of ((x)/(3)-(2)/(x^(2)))^(10) contains x^(4), then find the value of r

A=[{:(3,5),(-2,4):}] Find the adjoint of A.

If the function R rarr R is defined by f(x)=(x^(2)+1)^(35)AA in R then f is

alpha and beta are roots of the equation 2x ^(2)-35x+2=0. Find the value of sqrt((2alpha -35 )^(3) (2beta-35)^(2))