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Each side of a cube is measured to be 6.230 m. What is the total surface area and the volume of cube to appropriate significant figures?

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To solve the problem of finding the total surface area and volume of a cube with each side measuring 6.230 m, we will follow these steps: ### Step 1: Calculate the Total Surface Area of the Cube The formula for the total surface area (SA) of a cube is given by: \[ SA = 6a^2 \] where \( a \) is the length of one side of the cube. **Substituting the value of \( a \):** \[ SA = 6 \times (6.230 \, \text{m})^2 \] ### Step 2: Calculate \( (6.230 \, \text{m})^2 \) Calculating the square of the side length: \[ (6.230)^2 = 38.870529 \, \text{m}^2 \] ### Step 3: Calculate the Total Surface Area Now substituting back into the surface area formula: \[ SA = 6 \times 38.870529 \, \text{m}^2 = 233.223174 \, \text{m}^2 \] ### Step 4: Round to Appropriate Significant Figures The measurement 6.230 m has four significant figures. Therefore, we need to round the total surface area to four significant figures: \[ SA \approx 233.2 \, \text{m}^2 \] ### Step 5: Calculate the Volume of the Cube The formula for the volume (V) of a cube is given by: \[ V = a^3 \] **Substituting the value of \( a \):** \[ V = (6.230 \, \text{m})^3 \] ### Step 6: Calculate \( (6.230 \, \text{m})^3 \) Calculating the cube of the side length: \[ (6.230)^3 = 243.101227 \, \text{m}^3 \] ### Step 7: Round to Appropriate Significant Figures Again, since the measurement has four significant figures, we round the volume: \[ V \approx 243.1 \, \text{m}^3 \] ### Final Results - Total Surface Area: \( 233.2 \, \text{m}^2 \) - Volume: \( 243.1 \, \text{m}^3 \) ---

To solve the problem of finding the total surface area and volume of a cube with each side measuring 6.230 m, we will follow these steps: ### Step 1: Calculate the Total Surface Area of the Cube The formula for the total surface area (SA) of a cube is given by: \[ SA = 6a^2 \] where \( a \) is the length of one side of the cube. ...
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