What is the difference between the temperature of two bodies, if their temperatures are `(50+-0.2)^(@)C` and `(25+-0.6)^(@)C`?

Explanation

To find the difference between the temperatures of two bodies, we will follow these steps:

### Step 1: Identify the given temperatures and their uncertainties
Let:
- Temperature of the first body, \( \theta_1 = 50 \pm 0.2 \, ^\circ C \)
- Temperature of the second body, \( \theta_2 = 25 \pm 0.6 \, ^\circ C \)

### Step 2: Write the formula for the temperature difference
The temperature difference \( \Delta \theta \) is given by:
\[ \Delta \theta = \theta_1 - \theta_2 \]

### Step 3: Substitute the values into the formula
Substituting the values of \( \theta_1 \) and \( \theta_2 \):
\[ \Delta \theta = (50 \pm 0.2) - (25 \pm 0.6) \]

### Step 4: Simplify the expression
Now, we can simplify this expression:
\[ \Delta \theta = 50 - 25 \pm (0.2 + 0.6) \]
This gives us:
\[ \Delta \theta = 25 \pm (0.2 + 0.6) \]

### Step 5: Calculate the uncertainty
Now, calculate the uncertainty:
\[ 0.2 + 0.6 = 0.8 \]
Thus, we have:
\[ \Delta \theta = 25 \pm 0.8 \, ^\circ C \]

### Final Answer
The difference between the temperatures of the two bodies is:
\[ \Delta \theta = 25 \pm 0.8 \, ^\circ C \]

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