To the bottom of a vessel containing alcohol of density `800 kg//m^(3)` a capillary tube of length 24 cm and diameter 1 mm is fitted horizontally. The axis of the capillary tube is at a depth of 36 em from the surface of the alcohol. The coefficient of viscosity of alcohol is `0.0012 Ns//m^(2)`. Calculate the mass of alcohol flowing out in 10 minutes, assuming that the height of the alcohol remains constant.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify Given Values
- Density of alcohol, \( \rho = 800 \, \text{kg/m}^3 \)
- Length of the capillary tube, \( L = 24 \, \text{cm} = 0.24 \, \text{m} \)
- Diameter of the capillary tube, \( d = 1 \, \text{mm} = 0.001 \, \text{m} \)
- Radius of the capillary tube, \( r = \frac{d}{2} = 0.0005 \, \text{m} \)
- Depth of the capillary tube from the surface, \( h = 36 \, \text{cm} = 0.36 \, \text{m} \)
...