Water is nowing through a horizontal pipe of varying cross-section. At a certain point where the velocity is 0-24 m/s the pressure of water is 0-010 metre of mercury. What is the pressure at a point where the velocity is `0-48 m/s`?

Explanation

To solve the problem, we will use Bernoulli's equation, which relates the pressure, velocity, and height of a fluid in a streamline flow. Since the pipe is horizontal, we can ignore the height term. The equation can be simplified as follows:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Velocity at point A, \( V_1 = 0.24 \, \text{m/s} \)
- Pressure at point A, \( P_1 = 0.10 \, \text{m} \, \text{Hg} \)
- Velocity at point B, \( V_2 = 0.48 \, \text{m/s} \)
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