A pilot tube is shown in fig. the fluid in the tube is mercury of density `13,600 kg//m^(3)` and the difference in level of mercury in the tube is 6 cm. What is the speed of air flow ? Density of air is `1.25 kg//m^(-3)`

Explanation

Density of air `= rho =1.25 kg//m^(3)`
Density of liquid in the manometer ` = rho_m= 13600 kg//m^(3)`
Difference in the liquid levels in the maometer = `h= 6 xx 10 ^(-2) m`
` " " v= sqrt((2h(rho_m-rho)g)/(rho))`
`" " =sqrt((2xx6xx 10^(-2) xx (13600-1.25)xx9.8)/(1.25))`
` = 11.3.1 m//s`