Home
Class 11
PHYSICS
In a test experiment on a model aeroplan...

In a test experiment on a model aeroplane in a wind tunnel, the flow speeds on the upper and lower surfaces of the wing are `70 ms^(-1) and 63 ms^(-1)` respectively. What is the lift on the wing if its area is` 2.5 m^(2)`? Take the density of air to be` 1.3 kg m^(-3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of calculating the lift on the wing of a model aeroplane in a wind tunnel, we can use Bernoulli's principle. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Given Information - Speed on the upper surface of the wing, \( V_1 = 70 \, \text{m/s} \) - Speed on the lower surface of the wing, \( V_2 = 63 \, \text{m/s} \) - Area of the wing, \( A = 2.5 \, \text{m}^2 \) - Density of air, \( \rho = 1.3 \, \text{kg/m}^3 \) ### Step 2: Apply Bernoulli's Equation According to Bernoulli’s principle, the difference in pressure between the upper and lower surfaces of the wing can be expressed as: \[ \Delta P = \frac{1}{2} \rho (V_2^2 - V_1^2) \] Where: - \( \Delta P \) is the pressure difference, - \( V_1 \) is the velocity of air over the upper surface, - \( V_2 \) is the velocity of air over the lower surface. ### Step 3: Calculate the Pressure Difference Substituting the values into the equation: \[ \Delta P = \frac{1}{2} \times 1.3 \, \text{kg/m}^3 \times (63^2 - 70^2) \] Calculating \( 63^2 \) and \( 70^2 \): \[ 63^2 = 3969 \quad \text{and} \quad 70^2 = 4900 \] Now, calculate the difference: \[ 63^2 - 70^2 = 3969 - 4900 = -931 \] Now substituting back into the pressure difference equation: \[ \Delta P = \frac{1}{2} \times 1.3 \times (-931) \] Calculating this gives: \[ \Delta P = \frac{1}{2} \times 1.3 \times -931 = -605.15 \, \text{Pa} \] Taking the absolute value: \[ |\Delta P| = 605.15 \, \text{Pa} \] ### Step 4: Calculate the Lift Force The lift force \( F_{\text{lift}} \) can be calculated using the formula: \[ F_{\text{lift}} = \Delta P \times A \] Substituting the values: \[ F_{\text{lift}} = 605.15 \, \text{Pa} \times 2.5 \, \text{m}^2 \] Calculating this gives: \[ F_{\text{lift}} = 1512.875 \, \text{N} \] ### Final Answer The lift on the wing is approximately: \[ F_{\text{lift}} \approx 1512.87 \, \text{N} \]

To solve the problem of calculating the lift on the wing of a model aeroplane in a wind tunnel, we can use Bernoulli's principle. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Given Information - Speed on the upper surface of the wing, \( V_1 = 70 \, \text{m/s} \) - Speed on the lower surface of the wing, \( V_2 = 63 \, \text{m/s} \) - Area of the wing, \( A = 2.5 \, \text{m}^2 \) - Density of air, \( \rho = 1.3 \, \text{kg/m}^3 \) ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN FLUIDS

    ICSE|Exercise SELECTED PROBLEMS ( FROM VISCOSITY , STOKES LAW) |17 Videos
  • INTERNAL ENERGY

    ICSE|Exercise SELECTED PROBLEMS (FROM HEAT ENGINES)|21 Videos
  • OSCILLATIONS

    ICSE|Exercise SELECTED PROBLEMS (OSCILLATION IN A TUNNEL BORED THROUGH THE EARTH)|2 Videos

Similar Questions

Explore conceptually related problems

In a test experiment on a model aeroplane in a wind tunnel, the flow speeds on the upper and lower surfaces of the wing are 70ms^(-1) and 83ms^(-1) respectively. What is the lift on the wing, if its area is 2.5m^(2) ? Take the density of air to be 1.3kgm^(-3)

A plane is in level flight at constant speed and each of its two wings has an area of 25 m^(2) . If the speed of the air on the upper and lower surfaces of the wing are 270 km h^(-1) and '234 km h^(-1)' respectively, then the mass of the plane is (Take the density of the air =1 kg m^(-3) )

In a wind tunnel experiment the pressure on the upper and lower surfaces of the wings are 0.90 xx 10^(5) Pa and 0.91 xx10^(5) Pa respectively .If the area of the wings is 40 m^(2) the net liftng forcw on the wing is

What is the mass of air in a room measuring 10.0 m x 5.2 m x 2.5 m, if the density of air is 1.3 kg//m^3 ?

Two bodies of mases 5kg and 3kg are moving towards each other with 2ms^(-1) and 4ms^(-1) respectively. Then velocity of centre of mass is

Two bodies of masses 3 kg and 2 kg are moving towards wach other with 3ms^(-1) and 2ms^(-1) respectively. Then velocity of centre of mass is

The speed of flow past the lower surface of a wing of an aeroplane is 50ms^(-1) . What speed of flow over the upper surface will give a dynamic lift of 1000 pa ? Density of air =1.3 kgm^(-3)

Calculate the mass of air in a room of dimensions 4.5 m x 3.5 m x 2.5 m if the density of air at N.T.P. is 1.3 "kgm"^(-3)

Air is streaming past a horizontal airplane wing such that its speed is 90 ms^(-1) at the lower surface and 120 ms^(-1) over the upper surface. if the wing is 10 m long and has an average width of 2 m , the difference of pressure on the two sides and the gross lift on the wing respectively, are (density of air =1.3kgm^(-3) )

A plane is in level flight at constant speed and each of its wings has an area of 25m^(2) . If the speed of the air is 180km//h over the upper wing surface, determine the plane's mass . (Take air density to be 1 kg//m^(3) ). g=9.8m//s^(2) .

ICSE-MOTION IN FLUIDS -SELECTED PROBLEMS (FROM POISEUILLE.S FORMULA)
  1. In giving a patient blood transfusion the bottle is set up so that the...

    Text Solution

    |

  2. A capillary tube PQ of length 0.6 m and radius 4 xx 10^(-3) m is conn...

    Text Solution

    |

  3. The rate of flow of a liquid through a capillary tube of radius r is u...

    Text Solution

    |

  4. Calculate the mass of alcohol flowing in two minutes through a tube of...

    Text Solution

    |

  5. A liquid flows through two capillary tube under the same pressure head...

    Text Solution

    |

  6. A capillary tube of length 5 cm and diameter 1 mm is connected to a ta...

    Text Solution

    |

  7. Glycerine flows steadily through a horizontal tube of length 1.5m and ...

    Text Solution

    |

  8. An orifice of diameter 8 mm is made on one side of a tank in which wat...

    Text Solution

    |

  9. Water flows through a hose (pipe) whose internal diameter is 2 cm at a...

    Text Solution

    |

  10. Calculate the speed of efflux of kerosene oil from an orifice of a tan...

    Text Solution

    |

  11. The reading of pressure meter attached with a closed water pipe is 3.5...

    Text Solution

    |

  12. Water is maintained at a height of 10 min a tank. Calculate the diamet...

    Text Solution

    |

  13. The cylindrical tube of a spray pump has a cross-section of 8 cm^(2)...

    Text Solution

    |

  14. At what speed will the velocity of a stream of water be equal to 20 cm...

    Text Solution

    |

  15. In a test experiment on a model aeroplane in a wind tunnel, the flow s...

    Text Solution

    |

  16. A wide tank is filled with water and kerosene. The tank has a small ho...

    Text Solution

    |

  17. The diameter of a pipe at two points where a venturimeter is connected...

    Text Solution

    |

  18. A large storage tank is filled to a height h1. There is a hole at the ...

    Text Solution

    |

  19. The cross-section area of the pipe shown in Fig. is 50 cm^(2) at the ...

    Text Solution

    |