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One of the faces of a copper cube of sid...

One of the faces of a copper cube of side 7.7 cm is maintained at 100°C and the opposite face at 30°C. If the thermal conductivity of copper is `385 "Wm"^(-1) "K"^(-1)`. Calculate the rate of heat flow through the cube?

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To calculate the rate of heat flow through the copper cube, we can use the formula for heat conduction: \[ Q = \frac{k \cdot A \cdot (T_1 - T_2)}{x} \] Where: - \( Q \) is the rate of heat flow (in Watts or Joules per second), ...
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