In Lee's disc experiment two discs are separated by gap of thickness 5 mm. The space between the discs contains a gas of thermal conductivity `3.88 xx 10^(-5) "Wm"^(-1) "K"^(-1)`. At the steady state the temperature, of the two sides of discs are `368K and 333K`. If the area of cross-section the slab is 25 `"cm"^(2)`, calculate the quantity of heat crossing the gas per second.
Text Solution
AI Generated Solution
To solve the problem, we will use the formula for heat transfer through conduction, which is given by:
\[
Q = \frac{k \cdot A \cdot \Delta T}{d}
\]
where:
- \( Q \) = quantity of heat crossing per second (in watts, W)
...
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THERMAL CONDUCTION
ICSE|Exercise CONCEPTUAL SHORT ANSWER QUESTIONS WITH ANSWERS|8 Videos
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ICSE-THERMAL CONDUCTION-SELECTED PROBLEMS (Taken from the Previous Years ISC, AISSCE, HSSCE various States. Boards Roorke Qns & NCERT text) FROM EXPERIMENT TO DETERMINE K
