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The temperature of an elactric bulb chan...

The temperature of an elactric bulb changes from 2000K to 3000K due to a.c. voltage fluctuations. Calculate the percentage rise in electric power consumed ?

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To calculate the percentage rise in electric power consumed when the temperature of an electric bulb changes from 2000 K to 3000 K, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between power and temperature**: According to Stefan-Boltzmann Law, the power radiated by a black body is proportional to the fourth power of its absolute temperature: \[ P = k \cdot T^4 \] where \( P \) is the power, \( k \) is a constant (which includes the Stefan-Boltzmann constant and the area), and \( T \) is the temperature in Kelvin. 2. **Calculate initial and final power**: - For the initial power \( P_1 \) at \( T_1 = 2000 \, K \): \[ P_1 = k \cdot (2000)^4 \] - For the final power \( P_2 \) at \( T_2 = 3000 \, K \): \[ P_2 = k \cdot (3000)^4 \] 3. **Find the change in power**: The change in power \( \Delta P \) is given by: \[ \Delta P = P_2 - P_1 = k \cdot (3000^4) - k \cdot (2000^4) \] Factoring out \( k \): \[ \Delta P = k \cdot \left(3000^4 - 2000^4\right) \] 4. **Calculate the percentage rise in power**: The percentage rise in power is given by: \[ \text{Percentage Rise} = \frac{\Delta P}{P_1} \times 100 \] Substituting the expressions for \( \Delta P \) and \( P_1 \): \[ \text{Percentage Rise} = \frac{k \cdot (3000^4 - 2000^4)}{k \cdot (2000^4)} \times 100 \] The \( k \) cancels out: \[ \text{Percentage Rise} = \frac{3000^4 - 2000^4}{2000^4} \times 100 \] 5. **Calculate \( 3000^4 \) and \( 2000^4 \)**: - \( 3000^4 = (3 \times 10^3)^4 = 81 \times 10^{12} \) - \( 2000^4 = (2 \times 10^3)^4 = 16 \times 10^{12} \) 6. **Substitute these values back into the percentage rise formula**: \[ \text{Percentage Rise} = \frac{81 \times 10^{12} - 16 \times 10^{12}}{16 \times 10^{12}} \times 100 \] \[ = \frac{65 \times 10^{12}}{16 \times 10^{12}} \times 100 \] \[ = \frac{65}{16} \times 100 \] \[ = 4.0625 \times 100 = 406.25\% \] ### Final Answer: The percentage rise in electric power consumed is approximately **406.25%**.

To calculate the percentage rise in electric power consumed when the temperature of an electric bulb changes from 2000 K to 3000 K, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between power and temperature**: According to Stefan-Boltzmann Law, the power radiated by a black body is proportional to the fourth power of its absolute temperature: \[ P = k \cdot T^4 ...
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