Home
Class 12
MATHS
When f: R to R and g: R to R are two ...

When ` f: R to R and g: R to R ` are two functions defined by `f(x) = 8x^(3) and g(x) = = x^((1)/(3))` respectively and (g of ) (x) = k (f o g ) (x) , then k is

A

`4`

B

` 2`

C

` (1)/(2)`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( k \) in the equation \( g(f(x)) = k(f(g(x))) \) given the functions \( f(x) = 8x^3 \) and \( g(x) = x^{1/3} \). ### Step 1: Calculate \( g(f(x)) \) We start by substituting \( f(x) \) into \( g(x) \): \[ g(f(x)) = g(8x^3) \] Since \( g(x) = x^{1/3} \), we have: \[ g(8x^3) = (8x^3)^{1/3} \] Using the property of exponents, we simplify: \[ (8x^3)^{1/3} = 8^{1/3} \cdot (x^3)^{1/3} = 2 \cdot x = 2x \] ### Step 2: Calculate \( f(g(x)) \) Next, we substitute \( g(x) \) into \( f(x) \): \[ f(g(x)) = f(x^{1/3}) \] Using the definition of \( f(x) \): \[ f(x^{1/3}) = 8(x^{1/3})^3 \] Again, simplifying gives: \[ 8(x^{1/3})^3 = 8x \] ### Step 3: Set up the equation Now we have: \[ g(f(x)) = 2x \quad \text{and} \quad f(g(x)) = 8x \] According to the problem statement: \[ g(f(x)) = k(f(g(x))) \] Substituting the expressions we found: \[ 2x = k(8x) \] ### Step 4: Solve for \( k \) To isolate \( k \), we divide both sides by \( 8x \) (assuming \( x \neq 0 \)): \[ k = \frac{2x}{8x} = \frac{2}{8} = \frac{1}{4} \] Thus, the value of \( k \) is: \[ \boxed{\frac{1}{4}} \]
Promotional Banner

Topper's Solved these Questions

  • MODEL TEST PAPER -1

    ICSE|Exercise Secton - C|11 Videos
  • MODEL TEST PAPER 15

    ICSE|Exercise SECTIONS-C|11 Videos

Similar Questions

Explore conceptually related problems

f:R to R is a function defined by f(x)= 10x -7, if g=f^(-1) then g(x)=

If f: R to R and g: R to R be two functions defined as f(x)=2x+1 and g(x)=x^(2)-2 respectively , then find (gof) (x) and (fog) (x) and show that (fog) (x) ne (gof) (x).

If f: R to R and g: R to R be two functions defined as f(x)=x^(2) and g(x)=5x where x in R , then prove that (fog)(2) ne (gof) (2).

Let f: R->R , g: R->R be two functions defined by f(x)=x^2+x+1 and g(x)=1-x^2 . Write fog\ (-2) .

Let f : R rarr R and g : R rarr R be two given functions defined as f(x) = 3x^(2) + 2 and g(x) = 3x-1, AA x in R Then find [(gof)(x)] at x = 1.

Let [-1,1] to R and g : R to R be two functions defined by f(x)=sqrt(1-x^(2)) and g(x)=x^(3)+1 . Find the function f+g , f-g , fg and f//g .

Function f: R to R and g : R to R are defined as f(x)=sin x and g(x) =e^(x) . Find (gof)(x) and (fog)(x).

If f: R->R and g: R->R be functions defined by f(x)=x^2+1 and g(x)=sinx , then find fog and gof .

Let f:R to R, g: R to R be two functions given by f(x)=2x-3,g(x)=x^(3)+5 . Then (fog)^(-1) is equal to

If f: R to R, g , R to R be two funcitons, and h(x) = 2 "min" {f(x) - g(x),0} then h(x)=