1 kg of water having a volume of `10^(-3) m ^(3)` becomes `1.67 m^(3)` of steam when boiled at a pressure of one atmosphere. The heat of vapourization at this pressure is 540 kcal/kg. Calculate the increase in internal energy and the work done in expansion.

Explanation

To solve the problem step by step, we will calculate the work done during the expansion and the increase in internal energy using the first law of thermodynamics.

### Step 1: Convert the heat of vaporization to joules
The heat of vaporization is given as \(540 \, \text{kcal/kg}\). We need to convert this to joules.

\[ \text{Heat of vaporization} = 540 \, \text{kcal/kg} \times 4184 \, \text{J/kcal} = 2.26 \times 10^6 \, \text{J/kg} \]
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