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A lead bullet just melts when stopped by...

A lead bullet just melts when stopped by an obstacle. Assuming that 25% of heat is absrobed by the obstacle find the velocity of the bullet if the initial temperature was `27^(@)C.` Melting point of lead `= 327^(@)C,` specific heat of lead `=0.03 cal g ^(-1) ""^(@)C ^(-1).` Latent heat of fusion of lead `=6 cal g ^(-1).`

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To solve the problem, we will use the principle of conservation of energy. The kinetic energy of the bullet will be converted into heat energy, which will raise the temperature of the bullet and then melt it. ### Step-by-Step Solution: 1. **Identify the given data:** - Initial temperature of the bullet, \( T_i = 27^\circ C \) - Melting point of lead, \( T_m = 327^\circ C \) - Specific heat of lead, \( C = 0.03 \, \text{cal/g} \cdot {}^\circ C \) ...
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