Home
Class 11
PHYSICS
Calculate the minimum work that must be ...

Calculate the minimum work that must be done to compress 1.0 gm of hydrogen at N.T.P. to half its initial volume. Given `R =8.314 J mol ^(-1) K ^(-1).`

Text Solution

AI Generated Solution

To calculate the minimum work that must be done to compress 1.0 gm of hydrogen at N.T.P. to half its initial volume, we can follow these steps: ### Step 1: Convert the mass of hydrogen to moles We know that the molar mass of hydrogen (H₂) is approximately 2 g/mol. Therefore, the number of moles (n) in 1.0 g of hydrogen can be calculated as: \[ n = \frac{\text{mass}}{\text{molar mass}} = \frac{1.0 \, \text{g}}{2 \, \text{g/mol}} = 0.5 \, \text{mol} \] ...
Promotional Banner

Topper's Solved these Questions

  • INTERNAL ENERGY

    ICSE|Exercise SELECTED PROBLEMS (FROM HEAT ENGINES)|21 Videos
  • INTERNAL ENERGY

    ICSE|Exercise SELECTED PROBLEMS (FROM ISOTHERMAL AND ADIABATIC PROCESSES )|10 Videos
  • GRAVITATION

    ICSE|Exercise FROM THE HUBBLE TELESCOP|2 Videos
  • MOTION IN FLUIDS

    ICSE|Exercise SELECTED PROBLEMS (FROM POISEUILLE.S FORMULA) |19 Videos

Similar Questions

Explore conceptually related problems

Calculate the molar specific heat of diatomic gas at constant volume. (R=8.314" J "mol^(-1)K^(-1))

Calculate the molar specific heat of oxygen gas at constant volume. (R=8.314" J "mol^(-1)K^(-1))

Calculate the molar specific heat at constant volume of neon gas. (R=8.314J mol^(-1)K^(-1) )

Calculate the critical volume for one mole of hydrogen if the critical temperature is 240 K and its critical pressure is 12.8 atm. R = 8.31 J m o l^(-1) K ^(-1) .

Two moles of an ideal gas was heated isobarically so that its temperature was raised by 100 K. The heat absorbed during the process was 4000 J. Calculate (i) the work done by the gas, (ii) the increase in internal energy and (ii) the value of y for the gas [R =8.31 J mol ^(-1) K ^(-1) ].

The activation energy for the reaction: 2AB rarr A_(2)+B_(2)(g) is 159.7 kJ mol^(-1) at 500 K . Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy. (Given: 2.3 xx 8.314 J K^(-1) mol^(-1) xx 500 K = 9561.1 J mol^(-1) )

1 mole of gas expands isothermally at 37^(@)C . The amount of heat is absorbed by it until its volume doubled is (R= 8.31 J mol^(-1) K^(-1))

The molar entropy content of 1 mole of oxygen (O_(2)) gas at 300 K and 1 atm is 250 J mol e^(-1)K^(-1) . Calculate DeltaG when 1 mole of oxygen is expanded reversibility and isothermally from 300K , 1 atm to double its volume ( Take R=8.314J mol e^(-1)K^(-1),log e=2.303)

Calculate the work done by 0.1 mole of a gas at 27^(@)C to double its volume at constant pressure (R = 2 cal mol^(-1)K^(-1))

Calculate the amount of heat that must be supplied to 40 gm of nitrogen to raise its temperature by 45^(@)C at constant pressure if it is at room temperature. R = 8.3 J mol ^(-1) K ^(-1).