An ideal gas of volume 1 litre and at a pressure 8 atm undergoes an adiabatic expansion until its pressure drops to 1 atm and volume increase to 4 liters. Calculate the work done in the process (y = 1.5).

Explanation

To solve the problem of calculating the work done during the adiabatic expansion of an ideal gas, we will follow these steps:

### Step 1: Convert the given values to SI units
- Initial volume (V1) = 1 liter = \(1 \times 10^{-3}\) m³
- Final volume (V2) = 4 liters = \(4 \times 10^{-3}\) m³
- Initial pressure (P1) = 8 atm = \(8 \times 1.013 \times 10^5\) Pa = \(8.104 \times 10^5\) Pa
- Final pressure (P2) = 1 atm = \(1.013 \times 10^5\) Pa

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