The efficiency of a carnot engine is 40%, whose sink is at a temperature of 300 K. By how much should be temperature of the source be increased be get an efficiency of 60% ?

Explanation

To solve the problem step by step, we will use the formula for the efficiency of a Carnot engine, which is given by:

\[ \text{Efficiency} = 1 - \frac{T_{\text{sink}}}{T_{\text{source}}} \]

Where:
- \( T_{\text{sink}} \) is the temperature of the sink (in Kelvin).
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