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Evaluate : 8 cos ^(3) ""(pi)/(9)- 6cos...

Evaluate :
`8 cos ^(3) ""(pi)/(9)- 6cos ""(pi)/(9)`

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To evaluate the expression \( 8 \cos^3 \left( \frac{\pi}{9} \right) - 6 \cos \left( \frac{\pi}{9} \right) \), we can follow these steps: ### Step 1: Rewrite the expression We start with the expression: \[ 8 \cos^3 \left( \frac{\pi}{9} \right) - 6 \cos \left( \frac{\pi}{9} \right) \] We can factor out a common factor of \( 2 \): \[ = 2 \left( 4 \cos^3 \left( \frac{\pi}{9} \right) - 3 \cos \left( \frac{\pi}{9} \right) \right) \] ### Step 2: Use the cosine triple angle formula We know from trigonometric identities that: \[ \cos(3\theta) = 4 \cos^3(\theta) - 3 \cos(\theta) \] In our case, let \( \theta = \frac{\pi}{9} \). Therefore, we can rewrite the expression inside the parentheses: \[ 4 \cos^3 \left( \frac{\pi}{9} \right) - 3 \cos \left( \frac{\pi}{9} \right) = \cos(3 \cdot \frac{\pi}{9}) = \cos \left( \frac{\pi}{3} \right) \] ### Step 3: Evaluate \( \cos \left( \frac{\pi}{3} \right) \) We know that: \[ \cos \left( \frac{\pi}{3} \right) = \frac{1}{2} \] ### Step 4: Substitute back into the expression Now we can substitute this value back into our expression: \[ 2 \left( \cos \left( \frac{\pi}{3} \right) \right) = 2 \left( \frac{1}{2} \right) = 1 \] ### Final Answer Thus, the value of the original expression \( 8 \cos^3 \left( \frac{\pi}{9} \right) - 6 \cos \left( \frac{\pi}{9} \right) \) is: \[ \boxed{1} \] ---
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ICSE-COMPOUND AND MULTIPLE ANGLES -EXERCISE 5 (C )
  1. Evaluate : cos ""(pi)/(8) sin ""(pi)/(8)

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  2. Evaluate : (2 tan 22 (1^(@))/( 2 ))/(1 - tan ^(2) 22 (1^(@))/( 2))

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  3. Evaluate : 8 cos ^(3) ""(pi)/(9)- 6cos ""(pi)/(9)

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