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Prove that Lim(x to 0) (|x|)/x , x != 0 ...

Prove that `Lim_(x to 0) (|x|)/x , x != 0 ` does not exist .

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To prove that \(\lim_{x \to 0} \frac{|x|}{x}\) does not exist, we will evaluate the left-hand limit and the right-hand limit separately. ### Step 1: Evaluate the Right-Hand Limit We start by finding the right-hand limit as \(x\) approaches 0 from the positive side. \[ \lim_{x \to 0^+} \frac{|x|}{x} \] Since \(x\) is positive when approaching from the right, we have \(|x| = x\). Thus, we can rewrite the limit as: \[ \lim_{x \to 0^+} \frac{x}{x} = \lim_{x \to 0^+} 1 = 1 \] ### Step 2: Evaluate the Left-Hand Limit Next, we find the left-hand limit as \(x\) approaches 0 from the negative side. \[ \lim_{x \to 0^-} \frac{|x|}{x} \] Since \(x\) is negative when approaching from the left, we have \(|x| = -x\). Thus, we can rewrite the limit as: \[ \lim_{x \to 0^-} \frac{-x}{x} = \lim_{x \to 0^-} -1 = -1 \] ### Step 3: Compare the Left-Hand and Right-Hand Limits Now we compare the left-hand limit and the right-hand limit: - Right-hand limit: \(1\) - Left-hand limit: \(-1\) Since the left-hand limit and the right-hand limit are not equal: \[ \lim_{x \to 0^+} \frac{|x|}{x} \neq \lim_{x \to 0^-} \frac{|x|}{x} \] ### Conclusion Therefore, we conclude that: \[ \lim_{x \to 0} \frac{|x|}{x} \text{ does not exist.} \] ---
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