Find out the number of dominant individual in a population of 6000, if the frequency of recessive phenotype is 25%

Options

A. 3000
B. 4500
C. 1500
D. 2000

Answer

To solve the problem of finding the number of dominant individuals in a population of 6000, given that the frequency of the recessive phenotype is 25%, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Frequency of Recessive Phenotype**:
The problem states that the frequency of the recessive phenotype is 25%. This means that 25% of the population exhibits the recessive trait.

2. **Calculate the Frequency of Dominant Phenotype**:
Since the total frequency must equal 100%, we can find the frequency of the dominant phenotype by subtracting the recessive frequency from 100%.
\[ \text{Frequency of Dominant Phenotype} = 100\% - 25\% = 75\% \]

3. **Convert the Frequency to Decimal Form**:
To use this frequency in calculations, convert it from a percentage to a decimal.
\[ \text{Frequency of Dominant Phenotype (P)} = \frac{75}{100} = 0.75 \]

4. **Calculate the Number of Dominant Individuals**:
Now, to find the number of dominant individuals in the population, multiply the frequency of the dominant phenotype by the total population size.
\[ \text{Number of Dominant Individuals} = \text{Frequency of Dominant Phenotype} \times \text{Total Population} \]
\[ \text{Number of Dominant Individuals} = 0.75 \times 6000 = 4500 \]

5. **Conclusion**:
Therefore, the number of dominant individuals in the population is 4500.

### Final Answer:
The number of dominant individuals in the population is **4500**.

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