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Cards are numbered 1 to 25 . Two cards a...

Cards are numbered 1 to 25 . Two cards are drawn at random . Find the probability that number on one card is a multiple of 7 and on the other is a multiple of 11.

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To solve the problem of finding the probability that one card drawn is a multiple of 7 and the other is a multiple of 11, we can follow these steps: ### Step 1: Identify the total number of cards The total number of cards is given as 25. ### Step 2: Identify the multiples of 7 The multiples of 7 between 1 and 25 are: - 7 (7 × 1) - 14 (7 × 2) - 21 (7 × 3) Thus, there are **3 multiples of 7**. ### Step 3: Identify the multiples of 11 The multiples of 11 between 1 and 25 are: - 11 (11 × 1) - 22 (11 × 2) Thus, there are **2 multiples of 11**. ### Step 4: Calculate the total ways to choose 2 cards from 25 The total number of ways to choose 2 cards from 25 is given by the combination formula: \[ \text{Total ways} = \binom{25}{2} = \frac{25 \times 24}{2} = 300 \] ### Step 5: Calculate the favorable outcomes We need to consider two scenarios: 1. The first card is a multiple of 7 and the second card is a multiple of 11. 2. The first card is a multiple of 11 and the second card is a multiple of 7. #### Scenario 1: First card is a multiple of 7, second is a multiple of 11 - The number of ways to choose the first card (multiple of 7) = 3 - The number of ways to choose the second card (multiple of 11) = 2 Thus, the total ways for this scenario = \(3 \times 2 = 6\). #### Scenario 2: First card is a multiple of 11, second is a multiple of 7 - The number of ways to choose the first card (multiple of 11) = 2 - The number of ways to choose the second card (multiple of 7) = 3 Thus, the total ways for this scenario = \(2 \times 3 = 6\). ### Step 6: Calculate the total favorable outcomes The total favorable outcomes = Outcomes from Scenario 1 + Outcomes from Scenario 2 = \(6 + 6 = 12\). ### Step 7: Calculate the probability The probability \(P\) that one card is a multiple of 7 and the other is a multiple of 11 is given by: \[ P = \frac{\text{Total favorable outcomes}}{\text{Total ways to choose 2 cards}} = \frac{12}{300} = \frac{1}{25} \] ### Final Answer The probability that one card is a multiple of 7 and the other is a multiple of 11 is \(\frac{1}{25}\). ---
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