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Find graphically the minimum value of Z=...

Find graphically the minimum value of `Z=5x+7y`, subject to the constraints given below:
`2x+y ge 8, x +2y ge 0 and x, y ge 0`

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To find the minimum value of \( Z = 5x + 7y \) subject to the constraints, we will follow these steps: ### Step 1: Identify the Constraints The constraints given are: 1. \( 2x + y \geq 8 \) 2. \( x + 2y \geq 0 \) 3. \( x \geq 0 \) 4. \( y \geq 0 \) ### Step 2: Convert Inequalities to Equations To graph the constraints, we first convert the inequalities into equations: 1. \( 2x + y = 8 \) 2. \( x + 2y = 0 \) ### Step 3: Plot the Constraints #### For \( 2x + y = 8 \): - When \( x = 0 \): \( y = 8 \) (Point A: \( (0, 8) \)) - When \( y = 0 \): \( x = 4 \) (Point B: \( (4, 0) \)) #### For \( x + 2y = 0 \): - When \( x = 0 \): \( y = 0 \) (Point C: \( (0, 0) \)) - When \( y = 0 \): \( x = 0 \) (Point D: \( (0, 0) \)) ### Step 4: Determine the Feasible Region - The line \( 2x + y = 8 \) divides the plane, and we shade the area above this line since we need \( 2x + y \geq 8 \). - The line \( x + 2y = 0 \) also divides the plane, and we shade the area above this line since we need \( x + 2y \geq 0 \). - The feasible region is where all shaded areas overlap, which is in the first quadrant due to the constraints \( x \geq 0 \) and \( y \geq 0 \). ### Step 5: Find Intersection Points To find the vertices of the feasible region, we solve the equations: 1. \( 2x + y = 8 \) 2. \( x + 2y = 0 \) By substituting \( y = -\frac{x}{2} \) into \( 2x + y = 8 \): \[ 2x - \frac{x}{2} = 8 \implies \frac{4x - x}{2} = 8 \implies \frac{3x}{2} = 8 \implies x = \frac{16}{3} \] Substituting \( x = \frac{16}{3} \) back into \( y = -\frac{x}{2} \): \[ y = -\frac{8}{3} \] This point is not valid since \( y \) must be non-negative. ### Step 6: Evaluate Corner Points The corner points of the feasible region are: 1. \( (0, 8) \) 2. \( (4, 0) \) 3. \( (0, 0) \) Now we evaluate \( Z = 5x + 7y \) at these points: - At \( (0, 8) \): \( Z = 5(0) + 7(8) = 56 \) - At \( (4, 0) \): \( Z = 5(4) + 7(0) = 20 \) - At \( (0, 0) \): \( Z = 5(0) + 7(0) = 0 \) ### Step 7: Determine Minimum Value The minimum value of \( Z \) occurs at the point \( (4, 0) \) where \( Z = 20 \). ### Conclusion Thus, the minimum value of \( Z = 5x + 7y \) subject to the given constraints is \( \boxed{20} \).
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